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Closed 12 years ago.

i 欲上下页以下链接:

<a href="javascript: __doPostBack( ctl00$PlaceHolderMain$g_781eb52f_faa9_4d59_9cae_2baec06ac484 , dvt_firstrow={51};dvt_startposition={Paged=TRUE&amp;p_Created_x0020_Date=6%2f9%2f2009%208%3a33%3a19%20AM&amp;p_ID=216} );">
<img src="/_layouts/images/next.gif" border="0" alt="Next"></a></td></tr></table></div></td>

如何在java方案中继续前进

Answer 1

您是否尝试了HttpUnit? 它对一些基本 Java本有APIC。

Answer 2

这只是一种意见......,但从你提出的法典来看,这一联系是一种倒退,而不是传统的“联系”。您将需要在网页上点击这一链接,以便它能够做任何有意义的工作。

采用该守则不会(可能不会)工作。该页的密码将准确确定在发出后退时会发生什么情况。

在一切类似情况下,贵会议已经结束,退席将无所作为......

Do you own/control the page s code? If you do, can you post the ASP and codebehind?

Answer 3

ppd=TRUE&p_Created_x0020_Date=6%2f9%2f2009%208%3a 333a19%20AM&p_ID=216

我的猜测是,p_Created_Date,p_ID,是你必须经过的参数,才能进入下页。

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