Question

我有这样的数据结构:

employee
. department
. building
. sector
> number (this is a relationship to employeeData)



employeeData
. name
. position
. salary
> number (this is a relationship to employee)

这样,只有一名雇员。每名雇员的数据输入。

I have classes for all entities.

现在,我如何吸引每个与某个雇员人数相对应的雇员,然后是雇员人数相对应的雇员。

我需要的是:

“合格雇员” 雇员数据。

感谢

Answer 1

与此类似:

NSManagedObjectContext * context  = [[NSApp delegate] managedObjectContext];
NSManagedObjectModel   * model    = [[NSApp delegate] managedObjectModel];
NSDictionary           * entities = [model entitiesByName];
NSEntityDescription    * entity   = [entities valueForKey:@"Employee"];

NSPredicate * predicate;
predicate = [NSPredicate predicateWithFormat:@"number = %@", number];


NSFetchRequest * fetch = [[NSFetchRequest alloc] init];
[fetch setEntity: entity];
[fetch setPredicate: predicate];


NSArray * results = [context executeFetchRequest:fetch error:nil];
[fetch release];

Employee *emp = [results objectAtIndex:0];
EmployeeData *data = [emp data];

如果核心数据模型界定了关系,则认为数据关系自动到期。 http://www.coadev central.com/articles/000086.php“rel=“nofollow”http://www.coadevration.com/articles/000086.php>。

友情链接