Question

我希望有人能够指出,我在这里会错。 I m试图制造一个简单的过滤器,它做的是Paul Tuckey s URLRewriteFilter,但只做我需要做的事情。

我无法阻止它回到原来的《世界投资倡议》。我在《URLRewriteFilter法典》上宣布了出来,似乎正在做基本上相同的事情。我的过滤代码如下:

public static final String dispatcherURI = "/Dispatcher?q=";
public void doFilter(final ServletRequest request, final ServletResponse response,
                     final FilterChain chain)
        throws IOException, ServletException {
    final HttpServletRequest rq = (HttpServletRequest)request;
    final HttpServletResponseWrapper rsw =
        new HttpServletResponseWrapper((HttpServletResponse)response);
    final String uri = rq.getRequestURI();
    if (uriIsDispatchable(uri)) {
        final String forwardPath = dispatcherURI+uri;
        rq.getRequestDispatcher(forwardPath).forward(rq, rsw);
        LOG.info("Forward From: "+uri+", To: "+forwardPath);
    }
    else {
        try { chain.doFilter(request, response); }
        catch (Exception e) {
            LOG.error(e);
            throw new RuntimeException(e);
        }
    }
}

// checks URI against an ArrayList of URIs that should be ignored.
private static boolean uriIsDispatchable (final String uri) {
    boolean result = true;
    for (String i : ApplicationValues.uriIgnore) {
        if (uri.indexOf(i) == 0) {
            result = false;
            break;
        }
    }
    return result;
}

Here s the filter entry in web.xml

<filter>
    <filter-name>UrlRewriteFilter</filter-name>
    <filter-class>myapp.filter.URLRewrite</filter-class>
</filter>
<filter-mapping>
    <filter-name>UrlRewriteFilter</filter-name>
    <url-pattern>/*</url-pattern>
</filter-mapping>

Some notes on the code: A URI like /home should be forwarded to a dispatcher servlet like so: /Dispatcher?q=/home the dispatcher servlet then determines what code to execute based on what s in the query string.

过滤器正确地忽视了“uriIgnore”ArrayList(包括分机/分机)中的URIs,但前方在家留宿。为了完整起见,本文摘录了在上述各种可分的方法中检索的uriIgnore ArrayList的内容:

public static final List<String> uriIgnore = new ArrayList<String>(4);
static {
  uriIgnore.add("/Dispatcher");
  uriIgnore.add("/netbeans-tomcat-status-test");
  uriIgnore.add("/resources");
  uriIgnore.add("/robots.txt");
}

另外,我跑了最新的Tomcat 6号车.在阿帕奇。

感谢任何帮助。感谢。

Answer 1

I ll get around to figuring this out when I have time to peruse the URLRewrite Filter code further, but in the meantime it seems that if I really want the highest performance URL rewriting, I ll just let mod_rewrite and Apache do it.

我的解决办法(我确信,还有更好的办法这样做):

# .htaccess file contents
# Apache has the same docroot as the Java web app.
# Java webapp is running on port 8084
<IfModule mod_rewrite.c>
RewriteEngine On
RewriteBase /
RewriteCond %{REQUEST_FILENAME} !-f [NC,OR]
RewriteCond %{REQUEST_FILENAME} !-d
# directory where images, static html files and JS scripts are located.
# Apache will serve these.
RewriteRule ^resources - [L,NC]
# obviously, we want Apache to serve robots.txt
RewriteRule ^robots.txt$ - [L,NC]
RewriteRule ^(.*)$ http://localhost:8084/Dispatcher?q=$1 [L,P,QSA]
</IfModule>

Answer 2

I think when the program execute the statement: rq.getRequestDispatcher(forwardPath).forward(rq, rsw); it will call the doFilter() method again, and then the program will be an endless loop. I think you can add a parameter to tell the url is from another doFilter() or not, so it can recognize and then forward the url or not.

Answer 3

Same infinite loop problem here, configure urlrewriter to filter only REQUEST, not FORWARD, try something like this in your web.xml:

 <filter-mapping>
     <filter-name>UrlRewriteFilter</filter-name>
     <url-pattern>/*</url-pattern>
     <dispatcher>REQUEST</dispatcher>
 </filter-mapping>

在本案中,在移交后,规则处理不再执行。

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