文字运转良好,图像储存在一张叫上上载的夹中。
问题在于,如何回击我所描述的上载档案,以便我能够在我的网站上展示上载的形象。
感谢帮助!
您联系的法典(标题Saving the Uploaded file)中的最后一段文字指出,它得到了保存:
echo "Stored in: " . "upload/" . $_FILES["file"]["name"];
因此,假定<代码>upload ,即:src
。 将:
echo <img src="/upload/ .$_FILES["file"]["name"]. " /> ;
通常,视你的服务器配置,图像(或任何上载)上载。 你们需要把复印件放在你的网络名录上(可能放在像“超载图像”这样的子里)。 你也可以重新命名这一进程中的档案,因为其名称将是对手法23ur20dasjsdablah。 jpg
The uploaded file will be deleted if you do not copy it so. So copy it to either public or private directory, as in link w3school...:
move_uploaded_file($_FILES["file"]["tmp_name"],
"upload/" . $_FILES["file"]["name"]);
echo "Stored in: " . "upload/" . $_FILES["file"]["name"];
公开,如档案
<img src="path-to-img.jpg" />
and then the file needs to reside in a readable directory by the webserver. The default fileupload-directory is not readable, so copy the file.
私人,你利用Sphp为你找到档案:
<img src="getFile.php?filename=myfile.jpg">
//getFile.php
header( content-type: image/jpeg );
echo file_get_contents( myjpg.jpg );
regards, /t
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