我知道,这是一项轻松的任务,但在修改我的法典之后,它停止了工作,我可以把它带回来! 我利用两项职能来推敲和 un击,尽管它的实际作用是“jar”和“unjar”,但这不应带来巨大变化。
public static void zipit(File[] infiles, JarOutputStream jos) throws Exception
{
zipit(infiles,"", jos);
}
public static void zipit(File[] infiles, String root, JarOutputStream jos) throws Exception
{
byte[] buffer = new byte[4096];
for(int i=0; i<infiles.length; i++)
{
// recursive call for subfolders... temporary
if(infiles[i].isDirectory())
{
zipit(infiles[i].listFiles(), infiles[i].getName() + "/", jos);
continue;
}
// create string with absolute path
String entryfile = root + infiles[i].getName();
JarEntry entry = new JarEntry(entryfile);
zos.putNextEntry(entry);
FileInputStream fis = new FileInputStream(infiles[i]);
int count;
while((count = fis.read(buffer, 0, buffer.length)) != -1)
zos.write(buffer, 0, count);
}
}
public static void unzipit(File zipfile, File outputfolder) throws Exception
{
JarFile jar = new JarFile(zipfile);
for(Enumeration entries = jar.entries(); entries.hasMoreElements(); )
{
JarEntry entry = (JarEntry) entries.nextElement();
File unzipped = new File(outputfolder, entry.getName());
if (entry.isDirectory() && !unzipped.exists())
{
unzipped.mkdirs();
continue;
}
else if (!unzipped.getParentFile().exists())
unzipped.getParentFile().mkdirs();
FileOutputStream fos = new FileOutputStream(unzipped);
InputStream in = jar.getInputStream(entry);
byte[] buffer = new byte[4096];
int count;
while((count = in.read(buffer, 0, buffer.length)) != -1)
fos.write(buffer, 0, count);
fos.close();
}
}
Any help/suggestions?
错误是在造成JarFile时发生的:
java.util.zip.ZipException: error in opening zip file
at java.util.zip.ZipFile.open(Native Method)
at java.util.zip.ZipFile.<init>(ZipFile.java:131)
at java.util.jar.JarFile.<init>(JarFile.java:150)
at java.util.jar.JarFile.<init>(JarFile.java:114)