Question

我有Xml-file。我需要读一下,作一些改动,并向一些新目的地写新的改动版本。

我可以读、写和分发这一文件(DocumentBuilderFactory ,DocumentBuilder,,等等)。



但我无法找到拯救这一档案的方法。 是否有办法使其对准文本的看法(String)?

Answer 1

与此类似:

Transformer transformer = TransformerFactory.newInstance().newTransformer();
Result output = new StreamResult(new File("output.xml"));
Source input = new DOMSource(myDocument);

transformer.transform(input, output);

Answer 2

如果你使用xerces-j:

public void serialise(org.w3c.dom.Document document) {
  java.io.ByteArrayOutputStream data = new java.io.ByteArrayOutputStream();
  java.io.PrintStream ps = new java.io.PrintStream(data);

  org.apache.xml.serialize.OutputFormat of =
                      new org.apache.xml.serialize.OutputFormat("XML", "ISO-8859-1", true);
  of.setIndent(1);
  of.setIndenting(true);
  org.apache.xml.serialize.XMLSerializer serializer =
                      new org.apache.xml.serialize.XMLSerializer(ps, of);
  // As a DOM Serializer
  serializer.asDOMSerializer();
  serializer.serialize(document);

  return data.toString();
}

Answer 3

这将使你有可能确定Xml格式

new XMLWriter(new FileOutputStream(fileName),
              new OutputFormat(){{
                        setEncoding("UTF-8");
                        setIndent("    ");
                        setTrimText(false);
                        setNewlines(true);
                        setPadText(true);
              }}).write(document);

友情链接