Question

What s is the best (beauty and efficient in terms of performance) way to iterate over multiple arrays in Ruby? Let s say we have an arrays:

a=[x,y,z]
b=[ a , b , c ]

我希望:

x a
y b
z c

感谢。

Answer 1

<代码>zip 阵列物体的方法:

a.zip b do |items|
    puts items[0], items[1]
end

Answer 2

另一种办法是使用<代码>each_with_index。快速基准显示,这一比率略高于使用zi。

a.each_with_index do |item, index|
  puts item, b[index]
end

基准:

a = ["x","y","z"]
b = ["a","b","c"]

Benchmark.bm do |bm|
  bm.report("ewi") do
    10_000_000.times do
      a.each_with_index do |item, index|
        item_a = item
        item_b = b[index]
      end
    end
  end
  bm.report("zip") do
    10_000_000.times do
      a.zip(b) do |items|
        item_a = items[0]
        item_b = items[1]
      end
    end
  end
end

成果:

      user     system      total        real
ewi  7.890000   0.000000   7.890000 (  7.887574)
zip 10.920000   0.010000  10.930000 ( 10.918568)

Answer 3

>> a=["x","y","z"]
=> ["x", "y", "z"]
>> b=["a","b","c"]
=> ["a", "b", "c"]
>> a.zip(b)
=> [["x", "a"], ["y", "b"], ["z", "c"]]
>>

Answer 4

见。建造的沙丘“齐普”的比拉等于什么?

Answer 5

我愿在利用鲁比拉多阵列进行循环使用。希望这一帮助。

bigarray = []
bigarray << array_1
bigarray << array_2
bigarray << array_3
variableName = bigarray.transpose

variableName.each do |item1,item2,item3|

# do stuff per item
# eg 
puts "item1"
puts "item2"
puts "item3"

end

友情链接