Question

执行这一方案:

#include <iostream>
int main()
{
char *name = "abc";
int i = reinterpret_cast<int>(name);
std::cout<<i<<std::endl;
return 0;
}

我得出以下产出:

这一数字是多少? 它是一个记忆吗? 但是,记忆指的是什么? 是否将“abc”储存为记忆中的一系列特性?

感谢。

Answer 1

它没有定义。体积(int)可能不等于大小(char*)。我不敢肯定,如果适用严格的特例规则的话。

然而,在实践中,假定其规模确实平等(大多数为32个轨道平台),4202656将成为阵列中第一个特性的地址。我将更清洁地这样做:

#include <iostream>
int main()
{
   const char *name = "abc"; // Notice the const. Constant string literals cannot be modified.
   std::cout << static_cast<const void*>(name) << std::endl;
}

Answer 2

It is probably the address of the character a .
Though I don;t think this is guaranteed (i.e. an int may not be long enough to hold the address).

Answer 3

You probably want to look at the question: casting via void* instead of using reinterpret_cast

简短的答案是,这完全可能是什么。

Answer 4

This the memory address of the first character of "abc", so "a". Because an array is a pointer who point to the first value of the array.
If you do cout << *(name++) normaly "b" is printed.

因此,当<代码> 姓名/代码>时,你试图给那些指“a”的被殴打者投身。

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