我深思熟虑地记得我第一次AS2游戏。 正如我所解释的那样,最佳办法可能是一种面向目标的做法。
在AS2中,有自动输入物体的检测方法。 基尔库帕岛有一个良好的教学:
rel=“nofollow” http://www.kirupa.com/developer/actionscript/hittest.htm
并且
http://help.adobe.com/en_US/AS2LCR/Flash_10.0/help.html?content=00001314.html
首先,你希望用盒子生成你的箱子。 您的班子需要研究如下内容:
//Box.as pseudo-code
class Box {
var x_pos:Number;
var y_pos:Number;
var attachedToPlayer:Boolean;
function Box(_x:Number, _y:Number) {
this.x_pos = _x;
this.y_pos = _y;
}
//other code here
}
See this tutorial on how to honour a section to a Object in the Library:
。
To create a new Box, you d then use something like
box1 = new Box(100,200);
// creates a box at position 100x,200y
However, you ll 并且 want to store the blocks you want to pickup into some sort of array so you can loop through them. See http://www.tech-recipes.com/rx/1383/flash-actionscript-create-an-array-of-objects-from-a-unique-class/
例:
//somewhere near the top of your main method, or whereever your main game loop is running from - note Box.as would need to be in the same folder
import Box;
//...then, somewhere before your game loop
//create an array to hold the objects
var boxArray:Array = new Array();
//create loop with i as the counter
for (var i=0; i<4; i++)
{
var _x:Number = 100 + i;
var _y:Number = 100 + i;
//create Box object
var box:Box = new Box();
//assign text to the first variable.
//push the object into the array
boxArray.push(box);
}
同样,你们需要一个班子,在你们的游戏开始时,例如,创造新的运动员。
var player = new Player(0,0);
然后,你可以针对你在主要游戏圈子(即更新你的角色位置和其他游戏特性的圈子)的阵列,对你们的参与者进行点击。 这样做可能有更有效的方法,例如,目前被筛选的区块只有排位。
您的阵列一旦建立,就利用旁听器,对你们的游戏中的角色,例如,进行打击。
//assuming you have an array called boxArray and player object called player
for(var box in boxArray){
if (player.hittest(box)) {
player.attachObjectMethod(box);
}
}
对于“我们进入阵列的每一箱子,如果参与者正在触动箱子,则检查”来说,这基本上是假装。 如果盒子正在打上,则将盒子作为参与者类别中的一种方法(我任意称“ObjectMethod”)的理由。
随函附上“Method”,你可以界定某种行为,将盒子贴上角色。 例如,你可以在盒子中为你的箱子的x和头寸以及像托帕莱尔这样的叫作的 b豆制造一个固定和固定的方法。 当有人叫随ObjectMethod时,它将放下箱子,如在运动员中。
//include Box.as at the top of the file
import Box;
//other methods, e.g. constructor
//somewhere is the Player.as class/file
public function attachObjectMethod (box:Box) {
box.setattachedToPlayer(true);
//you could 并且 update fields on the player, but for now this is all we need
}
现附上 参与者与盒子的灯泡相勾结是真实的。 回到我们的游戏圈子中,我们会改变我们的路面,更新箱子的位置:
//assuming you have an array called boxArray and player object called player
for(var box in boxArray){
if (player.hittest(box)) {
player.attachObjectMethod(box);
}
box.updatePosition(player.get_Xpos, player.get_Ypos);
}
在我们的方框中,我们现在需要界定最新的经验:
//Box.as pseudo-code
class Box {
var x_pos:Number;
var y_pos:Number;
var attachedToPlayer:Boolean;
function Box(box_x:Number, box_y:Number) {
this.x_pos = box_x;
this.y_pos = box_y;
}
public function updatePosition(_x:Number, _y:Number) {
if (this.attachedToPlayer) {
this.x_pos = _x;
this.y_pos = _y;
}
}
//other code here
}
你可以看到,如果所附的ToPlayer boolean被设定,我们就能够通过参与者的立场,并更新箱子的位置。 最后,我们在方框中增加一个移动方法:
public function move() {
if (this.attachedToPlayer) {
this._x = x_pos;
this._y = y_pos;
}
}
Examples of updating position:
http://www.swinburne.edu.au/design/tutorials/P-flash/T-How-to-smoothly-slide-objects-around-in-Flash/ID-17/
Finally, to make it all work we need to call the move method in the game loop:
//assuming you have an array called boxArray and player object called player
for(var box in boxArray){
if (player.hittest(box)) {
player.attachObjectMethod(box);
}
box.updatePosition(player.get_Xpos, player.get_Ypos);
box.move();
}
You have 并且 specified that the blocks should only move with the player if they have nothing on top of them. When you call your attachedToPlayer method, you would 并且 need to run a foreach loop inside the method between the box and the objects that might sit on top of the box. You should now have a fair idea from the above code how to do this.
I appreciate that this is quite a lengthy answer, and I haven t had an opportunity to test all the code (in fact I m fairly positive I made a mistake somewhere) - don t hesitate to ask questions. My other advice is to understand the concepts thoroughly, and then write your own code one bit at a time.
亲爱!
