我有各种各样的 by子,如果从某个特定数字0开始,到9岁结束,到9岁时,我需要检查,但是在9年后,我拿到了数字。
e.g test[] = { 0, 1, 4, 5, 9, 10 };
test[] = { 0, 3, 2, 9, 6, 0, 4, 2, 9, 6 }; - in this there are two sets
是否有办法利用定期表达来发现这一点?
我有各种各样的 by子,如果从某个特定数字0开始,到9岁结束,到9岁时,我需要检查,但是在9年后,我拿到了数字。
e.g test[] = { 0, 1, 4, 5, 9, 10 };
test[] = { 0, 3, 2, 9, 6, 0, 4, 2, 9, 6 }; - in this there are two sets
是否有办法利用定期表达来发现这一点?
这不像我经常使用的语言,因此答案是没有的,你可以这样做。
如果名单的大小确定,或如你需要单元10号数的总和,就会非常复杂,但可能是可行的。 但是,一般说来的一种语言是,数字清单和数量的总和是固定的,因为它三度未能达到。
在积极的方面,如果不定期表达,就很容易做到。
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