First Alternative

Question

hide button class = "vc_button" from logged out user woocommerce I have tried

.logged-out .vc_button{
display: none;
}

&

<?php
if ( is_user_logged_in() ) {
    echo  Welcome, registered user! ;
} else {
    echo "<div class="vc_button" style="display:none"></div>";
}
?>

both of them not working ,how the button from class from logged out users , the button will be display for logged in users

Answer 1

First Alternative

Hi! It s probably because you are using double quotes to include the class name. You can alternate between single and double quotation marks like this:

if ( is_user_logged_in() ) {

    echo  Welcome, registered user! ;

} else {

    echo "<div class= vc_button  style= display: none; ></div>";

}

Every quotation mark has its own meaning in PHP. Double quotes allow you to insert variables in a string while the single ones not:

Double Quotes

$activity = "programming";

$string = "I love $activity";

echo $string; # I love programming

Single Quotes

$activity =  cooking ;

$string =  I love $activity ;

echo $string2; #I love $activity

Backticks

These are special because PHP will attempt to execute the contents of the backticks as a shell command and return the output (The backtick operator won t work when shell_exec() is disabled).

$host =  www.wuxiancheng.cn ;

$output = `ping -n 3 {$host}`;

echo "<pre>$output</pre>"; # Ping result

Second Alternative

You can also use a stops "." to concatenate strings with variables. You can use them between strings and variables like this:

$class = "vc_button";
$style = "display:none";

echo "<div class=" . $class . " style=" . $style . "></div>";

First Alternative

Double Quotes

Single Quotes

Backticks

Second Alternative

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