Question

我有一份以色人种格式的运动员名单。在使用假体时,我想 gr掉名册上的所有名字; at子和大体;名字,然后把它们插入倒塌的菜单。

但是,出于某种原因, lo不行。如果我看一看一看一看一看一看一看一看一看一看一看一看一看一看一看一看一看一看一看一看一看一看一看一去。难道我要混淆一下阵列和物体吗?

JSON代码

{
    "team": {
        "color": "000000",
        "country": "USA",
        "roster": [
            {
                "athlete": {
                    "name": "John Doe",
                    "age": 20
                }
            },
            {
                "athlete": {
                    "name": "Jane Doe",
                    "age": 21
                }
            },
            {
                "athlete": {
                    "name": "Jack Doe",
                    "age": 22
                }
            },
            {
                "athlete": {
                    "name": "Joe Doe",
                    "age": 23
                }
            }
        ]
    }
}

我有一份以色人种格式的运动员名单。在使用假体时,我想 gr掉名册上的所有名字; at子和大体;名字,然后把它们插入倒塌的菜单。

但是,出于某种原因, lo不行。如果我看一看一看一看一看一看一看一看一看一看一看一看一看一看一看一看一看一看一看一看一看一看一看一去。难道我要混淆一下阵列和物体吗?

JSON代码

{ "team": { "color": "000000", "country": "USA", "roster": [ { "athlete": { "name": "John Doe", "age": 20 } }, { "athlete": { "name": "Jane Doe", "age": 21 } }, { "athlete": { "name": "Jack Doe", "age": 22 } }, { "athlete": { "name": "Joe Doe", "age": 23 } } ] } } JS code

async function getAthletes() {

    const getPlayers = document.getElementById( getPlayers )

    await fetch( athlete.json , {
        method:  GET 
    })
    .then((response) => response.json())
    .then(data => {

        const athletes = data.team.roster[0].athlete

        for(let i = 0; i < athletes.length; i++) {
            getPlayers.inner传真 += `<option value="${athletes[i].name}">${athletes[i].name}</option>`
        }
    }) 
}

传真

<select id="getPlayers" data-category="Vote" data-action="click" data-label="Select Player">
    <option value="">Select player</option>
</select>

希望在会后再照此办理。

<select id="getPlayers" data-category="pick" data-action="click" data-label="Select Player">
    <option value>Select player</option>
    <option value="John Doe">John Doe</option>
    <option value="Jane Doe">Jane Doe</option>
    <option value="Jack Doe">Jack Doe</option>
    <option value="Joe Doe">Joe Doe</option>
</select>

Answer 1

仅看一下你在此做些什么:

const athletes = data.team.roster[0].athlete

u 重建一个称为运动员的变量,将其价值确定为运动员。仅举一例不是一件事。在这一行动中,你具体说明了阵列的指数0。如果你想走整个阵列,就不只使用其中的一项内容。使用整个阵列:

 const athletes = data.team.roster;

然后,阵列中的每一个要素都一样:

  "athlete": {
    "name": "John Doe",
    "age": 20
  }
}

提及在 lo体内的价值,就是:

 athletes[i].athlete.name

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