我刚开始测试Slickgrid对于我正在进行的一个项目,它的性能给我留下了深刻的印象。我的一个要求是对多列进行排序。我没有完全理解Slickgrid中的数据视图,所以可能我缺少了一些明显的东西,但有没有一种方法可以对多列上的网格进行排序?即使UI无法处理多个列的排序,我也希望能够调用按照列的顺序,加上升序或降序。我能够用数据表,但它没有分组(项目的另一个要求)。
在最坏的情况下,我将在服务器上进行排序,并将静态排序的内容返回给客户端。
您可以链接排序比较器来执行多列排序。而不是做
function comparerOnCol1(a, b) {
return a["col1"] - b["col1"];
}
function comparerOnCol2(a, b) {
return a["col2"] - b["col2"];
}
你可以
// sort by col1, then col2
function combinedComparer(a, b) {
return comparerOnCol1(a, b) || comparerOnCol2(a, b); // etc.
}
或者只是内联实现它。
至于在UI中反映排序顺序,虽然您不能直接这样做,但您可以通过在重新排序的列定义上设置“headerCssClass”并让它们显示箭头(或者以其他方式指示排序列)来应用排序指示符。
我用多列排序的方式为dataView工作。也是最容易理解的。这是来自github中的示例,只是我必须为dataView.sort()再传递一个参数。它可以始终为true,并且您可以在函数中处理排序方向。
grid.onSort.subscribe(function (e, args) {
gridSorter(args.sortCols, dataView);
});
function gridSorter(sortCols, dataview) {
dataview.sort(function (row1, row2) {
for (var i = 0, l = sortCols.length; i < l; i++) {
var field = sortCols[i].sortCol.field;
var sign = sortCols[i].sortAsc ? 1 : -1;
var x = row1[field], y = row2[field];
var result = (x < y ? -1 : (x > y ? 1 : 0)) * sign;
if (result != 0) {
return result;
}
}
return 0;
}, true);
}
以防万一它能帮助到别人。
这里有一个使用multiColumnSort选项的示例。
http://mleibman.github.com/SlickGrid/examples/example-multi-column-sort.html
不过我认为它不起作用,因为args.sortCols总是一个1的数组。
[Edit] In order for it work, I need to hold shift before clicking on a column header (not very intuitive IMHO) See also: https://github.com/mleibman/SlickGrid/pull/276
我花了一段时间试图用dataview解决这个问题(没有移位键的恶作剧),我想我找到了解决这个问题的方法。
使用单列排序{multiColumnSort:false}
并将排序参数存储在闭包中。如果字段相等,则延迟到上一个比较器。
var currentSortCmp = null;
grid.onSort.subscribe(function (e, args) {
// declarations for closure
var field = args.sortCol.field;
var sign = args.sortAsc ? 1 : -1;
var prevSortCmp = currentSortCmp;
// store closure in global
currentSortCmp = function (dataRow1, dataRow2) {
var value1 = dataRow1[field], value2 = dataRow2[field];
//if equal then sort in previous closure (recurs)
if (value1 == value2 && prevSortCmp)
return prevSortCmp(dataRow1, dataRow2);
return (value1 == value2 ? 0 : (value1 > value2 ? 1 : -1)) * sign;
};
dataView.sort(currentSortCmp);
grid.invalidate();
grid.render();
});
记住以前的所有订单。只是起作用。如预期工作。
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