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MySQL使用join选择where in但不选择in
原标题:MySQL select where in but not in with join

我的数据库中有三个表:

产品

  • id (int, primary key)
  • name (varchar)

标签

  • id (int, primary key)
  • name (varchar)

产品标签

  • product_id (int)
  • tag_id (int)

我正在执行SQL查询,以选择具有指定id的已分配标签的产品:

SELECT * FROM Products
JOIN ProductTags ON Products.id = ProductTags.product_id
WHERE ProductTags.tag_id IN (1,2,3)
GROUP BY Products.id

我可以选择没有指定标识的产品:

SELECT * FROM Products
JOIN ProductTags ON Products.id = ProductTags.product_id
WHERE ProductTags.tag_id NOT IN (4,5,6)
GROUP BY Products.id

我如何结合这些查询来选择具有给定标签但没有其他标签的产品?我试图通过这种方式实现这一点:

SELECT * FROM Products
JOIN ProductTags ON Products.id = ProductTags.product_id
WHERE ProductTags.tag_id IN (1,2,3)
AND ProductTags.tag_id NOT IN (4,5,6)
GROUP BY Products.id

但它显然不起作用,给我带标签(1,2,3)的产品,无论它们是否分配了标签(4,5,6)。是否可以使用一个查询来解决此问题?

最佳回答

使用子查询筛选出包含不需要的标记的产品列表:

SELECT * FROM Products
  JOIN ProductTags ON Products.id = ProductTags.product_id
  WHERE ProductTags.tag_id IN (1,2,3)
    AND Products.id NOT IN (SELECT product_id FROM ProductTags WHERE tag_id IN (4,5,6))
  GROUP BY Products.id
问题回答

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