Question

我很想知道,XPath是否能够恢复一系列价值。

我有这样的想法:

<Cities>
    <City>Paris</City>
    <City>Lyon</City>
    <City>Marseille</City>
</Cities>

我也想获得一系列这样的形式[巴黎、里昂、马赛]。

I am using the xpath UNIX utility.

任何想法?

Answer 1

除后处理外,还产出:

xpath -q -e  //City/text()  inputfile

:

Paris
Lyon
Marseille

(a) 以各种方式,包括:

xpath -q -e  //City/text()  inputfile |
    awk  BEGIN {sq = "47"; OFS = sq "," sq}
         {a[$1] = NR}
         END {
             printf "[" sq; 
             for (i in a) {
                 printf "%s%s", d, i; d = OFS};
             print sq "]"
         }

产出:

[ Lyon , Marseille , Paris ]

您可使用经修改的<代码>xpath。既然是简单的Perl书,我修改了该书,使你对产出格式有了更大的控制。有了我的版本,你可以做到:

xpath -q -b "[" -p " " -i "," -s " " -a "]"$ 
  -e  //City/text()

获取预期产出。这里是使用信息:

Usage:
xpath [options] -e query [-e query...] [filename...]

        If no filenames are given, supply XML on STDIN.
        You must provide at least one query. Each supplementary
        query is done in order, the previous query giving the
        context of the next one.

        Options:

        -q quiet        Only output the resulting PATH
        -b before       use before instead of nothing.
        -p prefix       use prefix instead of nothing.
        -s suffix       use suffix instead of linefeed.
        -i infix        use infix instead of nothing.
        -a after        use after instead of nothing.

页: 1 下载我的版本。

Answer 2

www.un.org/Depts/DGACM/index_spanish.htm The XPath expression:

/*/*/text()

确切地选择了三个希望的案文节点。

www.un.org/Depts/DGACM/index_spanish.htm 您可以使用各种像样的编号:

/*/*/text()[1]

案文选择

"Paris"

,

/*/*/text()[2]

案文选择

"Lyon"

,

/*/*/text()[3]

案文选择

"Marseille"

www.un.org/Depts/DGACM/index_spanish.htm 如果你只想看这些案文的任何节点的可见价值,则使用(例如):

string(/*/*/text()[2])

对这一口号进行评价的结果是说明

"Lyon"

Answer 3

i 知道。您可在xmlDocument上查阅;xDoc.SelectNodes("/City”);中向您提供一份节点清单,每个节点均可填写。

友情链接