Question

我试图找到能够找到“C:/”。

我的法典是:

String test = "C:\";  
String regex = "[a-z]*[A-Z]*[:]*\";  
if(test.matches(regex))  
    System.out.println("Success!");  
else  
    System.out.println("Failure!");

I m 正在获得SyntaxException。我用许多定期的措辞进行了审判,结果也是一样的。

我如何解决这一问题?

Answer 1

简单(但可能是无用的)答案是“......”。

在此情况下,你显然希望更接近:[a-zA-Z]:。这完全需要一封信,然后是上校,然后是回击。假设你的扼杀本应代表视窗上某些磁盘的根基,它应当比你在任何情况下的更接近。

Answer 2

顺序在大多数语文中具有特别的意义。正因为如此,它选择了一条道路。您在此提出的问题是,它具有特别的意义,具有定期表达。也就是说,在常规表述中,>_______________________________________ 。

BTW 我认为,你们需要的是“[a-zA-z]:吗?”

OMG对SO也有特别意义:P

Answer 3

你们需要把越狱一度,一度是 Java的越狱,一度是reg的越狱:

String test = "C:\";
String regex = "[a-zA-Z]:\\";
if ...

Answer 4

If you are trying to find C: explicitly, you could just use String regex ="C:\"; Not very flexible, but fits exactly.

What you are likely looking for is something like String regex = "[A-Z]:\\"; That says to "Match a single character in the range between "A" and "Z"" then "Match the character ":"" then "Match the character ". If you need to include lowercase beginning letters use String regex = "[a-zA-Z]:\\"; which matches a single character either between "a" and "z" or between "A" and "Z".

Answer 5

为什么不只使用<代码>String.contains ("C:/”)?

友情链接