我怎么能够有2个或2个以上不同期限的动画,但同时也开始。
when I do something like (for example)
$("#something").animate({opacity: 1}, 2500).animate({left: 1000}, 10000);
我怎么能够有2个或2个以上不同期限的动画,但同时也开始。
when I do something like (for example)
$("#something").animate({opacity: 1}, 2500).animate({left: 1000}, 10000);
http://api.jquery.com/animate/“rel=“nofollow” 您可以设定一个名为<代码>queue=false的财产,以便取得你想要的效果。 修订法典:
$("#something")
.animate({opacity: 1, queue: false}, 2500)
.animate({left: 1000 +"px", queue: false}, 10000);
我希望:
PS。 一种推测带有queue=false
财产,因此,你可以将物体的其他消化。 在此情况下,您可能会wan缩到跳跃上最后一刻的<代码>queue=fal>,因此,链式的估算只能从词汇中得出最长的估算。 例如,如果在你目前估计之后,你也想把高点推到一起:
$("#something")
.animate({opacity: 1, queue: false}, 2500)
.animate({left: 1000 +"px"}, 10000)
.animate({height: 500 +"px"}, 1000);
这样,<条码>八<>/代码>只有在条码/代码终止后才算。
http://docs.jquery.com/Release:jQuery_1.2/Effects#Simultaneous_Animations”rel=“nofollow” http://docs.jquery.com/Release:jQuery_1.2/Effects#Simultaneous_Animations
我认为,这样做是trick的,尽管你可能只需要 que子:一种 an的虚假财产。
$("#something")
.animate({opacity: 1}, {queue: false, duration: 2500})
.animate({left: 1000}, {queue: false, duration: 10000});
问题
$("#something").animate({opacity: 1,left:1000}, 2500)
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