对于每一个问题,甚至像实体的SlectT*这样的简单问题,评估引擎都维持了两个指数,一个是按排位顺序排列的,另一个是按排位顺序排列的。 然后,它找到了第一个配对行,直到它找到一个非配对的行,并收回结果。
但为什么? 我不理解,为什么哪一个机制可以用来回避问题,特别是由于指数增加一倍而造成空间惩罚。 为此必须有一个很好的理由。
对于每一个问题,甚至像实体的SlectT*这样的简单问题,评估引擎都维持了两个指数,一个是按排位顺序排列的,另一个是按排位顺序排列的。 然后,它找到了第一个配对行,直到它找到一个非配对的行,并收回结果。
但为什么? 我不理解,为什么哪一个机制可以用来回避问题,特别是由于指数增加一倍而造成空间惩罚。 为此必须有一个很好的理由。
我可以肯定地说,但我的猜测是,GAE数据库的顶端是Bigtable (think “Sharded Sorted Array”)。
当扫描(思考关于退还批量的详细询问)进行时,可能更快地从磁盘中读出,而且可能最优化做些什么。 转向相反方向需要许多磁盘,这将减缓事情。
瑞安·巴雷特就Bigtable和数据库进行了很好的交谈;他就扫描上进行了会谈。
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