If I have some function y[x_]:=ax+b (just an example), how do I obtain x[y_]:=(y-b)/a in Mathematica? I ve tried InverseFunction,Collect and they don t work.
视之为方程式和使用<代码> Solve。
In:=Solve[y-ax-b==0,x]
Out={{x -> (-b + y)/a}}
如果你想要确定一项职能,你可以做到:
x[y_] := x /. Solve[y == a x + b, x][[1]]
x[1]
-> (1 - b)/a
rel=“nofollow”http://mathworld.wolfram.com/InverseFunction.html
具体如下:
In Mathematica, inverse functions are represented using InverseFunction[f].
一种办法是:
In[29]:= Solve[y == a x + b, x]
Out[29]= {{x -> (-b + y)/a}}
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