您是否希望将<代码>ints改为chars?

int yourInt = 33;
char ch = (char) yourInt;
System.out.println(yourInt);
System.out.println(ch);
// Output:
// 33
// !

还是想将<条码>ints改为String?

int yourInt = 33;
String str = String.valueOf(yourInt);

或者你指的是什么?

If you first convert the int to a char, you will have your ascii code.

例如:

    int iAsciiValue = 9; // Currently just the number 9, but we want Tab character
    // Put the tab character into a string
    String strAsciiTab = Character.toString((char) iAsciiValue);

有许多办法(视您的需要)转换为ASCII(ASCII),但这里是一种将每一分类的星体转换为ASCII特性的方法:

private static String toASCII(int value) {
    int length = 4;
    StringBuilder builder = new StringBuilder(length);
    for (int i = length - 1; i >= 0; i--) {
        builder.append((char) ((value >> (8 * i)) & 0xFF));
    }
    return builder.toString();
}

例如,ASCII“TEST”文本可作为星体表示:

byte[] test = new byte[] { (byte) 0x54, (byte) 0x45, (byte) 0x53, (byte) 0x54 };

然后,你可以做以下工作:

int value = ByteBuffer.wrap(test).getInt(); // 1413829460
System.out.println(toASCII(value)); // outputs "TEST"

......这样基本上将四位按32轨的 in合转化为4种不同的ASCII特性(一种特性是每 by)。

你们可以在 j将一些数字转换到ASCII。 例如,将第1号(基数为10)改为ASCII。

char k = Character.forDigit(1, 10);
System.out.println("Character: " + k);
System.out.println("Character: " + ((int) k));

产出:

Character: 1
Character: 49

In fact in the last answer String strAsciiTab = Character.toString((char) iAsciiValue); the essential part is (char)iAsciiValue which is doing the job (Character.toString useless)

Meaning the first answer was correct actually char ch = (char) yourInt;

如果在您的打字中(或0x31),时间为1

在 Java,你真的希望使用Integer.toString,将体格转换为相应的固定价值。 如果你只处理0-9位数,那么你就可以使用这样的东西:

private static final char[] DIGITS =
    { 0 ,  1 ,  2 ,  3 ,  4 ,  5 ,  6 ,  7 ,  8 ,  9 };

private static char getDigit(int digitValue) {
   assertInRange(digitValue, 0, 9);
   return DIGITS[digitValue];
}

private static int ASCII_ZERO = 0x30;

private static char getDigit(int digitValue) {
  assertInRange(digitValue, 0, 9);
  return ((char) (digitValue + ASCII_ZERO));
}

String result = Character.toString( yourAsciiNumber ) ;

Character.toString( 97 )   // LATIN SMALL LETTER A

Character.toString( 128_567 )   // FACE WITH MEDICAL MASK

Java的<条码>类型是遗产,基本上被打破。 作为16-bit Value,char无法代表。

System.out.println( Character.toString( 128_567 ));  // Unicode code points handle full-range of Unicode characters.

System.out.println( ( char ) 128_567 );  // `char` fails with most Unicode characters. 

见上运行。

Use code point integer numbers to represent individual letters.

US-ASCII是Unicode的一个子集。 因此,任何US-ASCII号(0-127)也是统法协会编码点(0-1,114,111)。

To change a code point number to a String object containing a single character, call Character#toString.

String x = Character.toString( 97 ) ;

a

见:Ide One.com。

最简单的方法是使用类型:

public char toChar(int c) {
    return (char)c;
}

The most simple way is to get integer and just use the casting operator Ex

int num = 33;
System.out.println((char) num);    //Outputs 33

//if you want to find the integer value of character instead.
//Just do the reverse

char ch =  % ;
System.out.println((int) ch);