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问题!
原标题:Question about .stop() in jQuery !

我知道,“站式”功能被用于阻止im灭。

$( #home ).mouseover(function(){
    $( .subhome_icon ).animate({
        "width":"5px",
        "opacity":"1.0"
    },1);
    $( .subhome_icon ).animate({
        "height":"15px"
    },1000);
    $( .subhome_icon ).animate({
        "width":"60px"
    },1000);
}).mouseout(function(){
    $( .subhome_icon ).animate({
        "opacity" :"0.0"
    },1000);
});

And I want to stop the animation when I leave the icon with the mouse pointer ! I ve wathced many jQuery videos but the examples are with one animation .. I ve got 3 !?

感谢你们! iii

问题回答

......

$( #home ).mouseover(function(){ 
    $( .subhome_icon ).animate({ "width":"5px", "opacity":"1.0" },1); 
    $( .subhome_icon ).animate({ "height":"15px" },1000); 
    $( .subhome_icon ).animate({ "width":"60px" },1000); })
.mouseout(function(){ 
    $( .subhome_icon ).stop().animate({ "opacity" :"0.0" },1000); 
});

你们需要使用

.mouseout(function(){ 
    $( .subhome_icon ).stop(true).animate({ 
                            "opacity" :"0.0" },
                         1000); 
});

(notice the true debate adopted to the .stop(meth)

这表明了令人沮丧的估算,使之真正停止目前的状况。





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