Question

After searching for an answer in other posts, I felt I have to ask this. I looked at How do I check if an array includes an object in JavaScript? and Best way to find if an item is in a JavaScript array? and couldn t get the code there to work.

我正在把第html号编码纳入一个阵列,因此每个项目都属于第html号。

例如:

i[0]= <param name="bgcolor" value="#FFFFFF" /> 
i[1]= <param name="width" value="640" /> 
i[2]= <param name="height" value="360" />    
i[3]= more html code

我想搜索这个阵列,并找到一个字高点。

理想的情况是,我要写出一份职务,把高点的项目列入议程。

幸运的是,这一阵列没有重复,因此只有一次发生。

我获得虚假的回报。

任何想法?

Answer 1

它简单易行,因为它使阵列变得更迭,并寻求实行管制。

function searchStringInArray (str, strArray) {
    for (var j=0; j<strArray.length; j++) {
        if (strArray[j].match(str)) return j;
    }
    return -1;
}

<<>Edit>/strong> - 成为str<>/code>的论据。

Answer 2

You can use Array.prototype.find function in javascript. Array find MDN.

因此,为了在一系列扼杀中找到证据,该法典变得非常简单。加上执行浏览器,它将提供良好的业绩。

页: 1

var strs = [ abc ,  def ,  ghi ,  jkl ,  mno ];
var value =  abc ;
strs.find(
    function(str) {
        return str == value;
    }
);

或使用《玛尔布达宣言》

var strs = [ abc ,  def ,  ghi ,  jkl ,  mno ];
var value =  abc ;
strs.find((str) => str === value);

Answer 3

1. 扩大你与以下事项相关的职能:

containsRegex(a, regex){
  for(var i = 0; i < a.length; i++) {
    if(a[i].search(regex) > -1){
      return i;
    }
  }
  return -1;
}

接着,你用一系列的体力和reg子来形容这一功能,就你而言,要看高度:

containsRegex([  <param name="bgcolor" value="#FFFFFF" /> ,  sdafkdf  ], /height/)

此外,如果发现高点,你还可以返回指数:

containsRegex(a, regex){
  for(var i = 0; i < a.length; i++) {
    int pos = a[i].search(regex);
    if(pos > -1){
      return [i, pos];
    }
  }
  return null;
}

Answer 4

较快到。如果你只是试图在一系列扼杀性价值观中找到第一种替代物,则使用“号”定期表述。你可以补充你自己的阵列搜索功能:

<><><>>:>

Array.prototype.findFirstSubstring = function(s) {
            for(var i = 0; i < this.length;i++)
            {
                if(this[i].indexOf(s) !== -1)
                    return i;
            }
            return -1;
        };

<>Usage:

i.findFirstSubstring( height );

<>Returns:

-1,如果找不到,或发现第一个次位次点的阵列指数(如果是2)

Answer 5

简单和大法典,支持多语

let strArray = ["Please locate where  locate  occurs!","Hi Hashem it","do it","for free"];

strArray.filter(word=> word.includes("it"));
Output
//Hi Hashem it,do it

//-------------------

strArray.filter(word=> word.includes("do it"));
Output
//do it

Answer 6

如果有人想进行某种动态的搜索,则会发生这种情况。

 let searchInArray=(searchQuery, array, objectKey=null)=>{

  return array.filter(d=>{
      let data =objectKey? d[objectKey] : d //Incase If It s Array Of Objects.
       let dataWords= typeof data=="string" && data?.split(" ")?.map(b=>b&&b.toLowerCase().trim()).filter(b=>b)
      let searchWords = typeof searchQuery=="string"&&searchQuery?.split(" ").map(b=>b&&b.toLowerCase().trim()).filter(b=>b)

     let matchingWords = searchWords.filter(word=>dataWords.includes(word))

    return matchingWords.length

})
    
    
}

a 阵列:

let arrayOfStr = [
  "Search for words",
  "inside an array",
  "dynamic searching",
  "match rate 90%"
]

searchInArray("dynamic search", arrayOfStr)

//Results: [ "Search for words", "dynamic searching" ]

物体:

let arrayOfObject = [
  {
    "address": "Karachi Pakistan"
  },
  {
    "address": "UK London"
  },
  {
    "address": "Pakistan Lahore"
  }
]

searchInArray("Pakistan", arrayOfObject,"address")

//Results: [ { "address": "Karachi Pakistan" }, { "address": "Pakistan Lahore" } ]

Answer 7

var newArr= [];
function searchStringInArray (str, strArray) {
       newArr = [];
    strArray.map(item => {
        str.includes(item) ? newArr.push(item) :   ;
    });
  return newArr;
}

var result = searchStringInArray( Definitely",he said in a matter-of-fact tone. , [ matter ,  definitely ]);

console.log(result);

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>

Answer 8

在一阵列内搜寻,你可以简单地使用Iteration methods(每个/地图),并在使用时使用。 Java 搜索方法

参考。 https://www.w3schools.com/jsref/jsref_search.asp

<><>Example>

const arrayOfLists = [ ape , apple , auto ]; const searchString = "A" let matchingStrings = []; arrayOfLists.forEach((list) => { if (list.toLocaleLowerCase().search(searchString.toLocaleLowerCase()) > -1) { matchingStrings.push(list) } })

<>平坦>阵列将列出所有可能发生事件的清单

友情链接