Question

am trying to use a php function within my html code but it keeps treating this block as a comment!(colored green in the source and not outputting anything) though i used the same function in another file and it worked just fine even within html...

function x (){
$x =  hello ;

echo( <marquee direction="left" scrollamount="3" behavior="scroll" style="width:300px;

height: 15px; font-size: 11px;"> );

echo $x;

echo </marquee> ;

}


<?php

echo x();

?>

The html file am using is a template i found online...any suggestions for what i should be checking?
Thanks!

Answer 1

这里的工作将:

<?php

function x (){
$x =  hello ;

echo( <marquee direction="left" scrollamount="3" behavior="scroll" style="width:300px;

height: 15px; font-size: 11px;"> );

echo $x;

echo </marquee> ;

}



x(); // Not echo, because the function doesn t return a value.

?>

此处略为黑体字:

<?php

function x ($message){

$html =  <marquee direction="left" scrollamount="3" behavior="scroll" style="width:300px; height: 15px; font-size: 11px;"> .$message. </marquee> ;

return $html;

}



echo x( hello );

?>

Answer 2

Coupe of things about the code you pasted:

<代码>x(>也必须在<?php和?> tags to be treatment as php Code。
页: 1

Answer 3

职能本身需要在各界进行总结。

友情链接