然而,我知道两个汽车司机从一个数据库中抽出,但我想只打其中的一辆汽车,并在Sphp上照搬。 我能够从司机那里获得详细情况,并重复使用假肢,而不只是针对其中之一:
我通过使用以下守则,重复了这两个记录。 难道有办法让其中一人感到贪 gr吗?
while($row = mysql_fetch_array($result))
{
echo "A driver:<br />";
echo "Name:". $row[ FirstName ] . " " . $row[ LastName ]."<br />";
echo "Latitude:". $row[ CoordLat ]."<br />";
echo "Longitude:". $row[ CoordLong ];
$driverlat = $row[ CoordLat ];
$driverlong = $row[ CoordLong ];
}//end of while loop
仅删除<条码>。
$row = mysql_fetch_array($result))
echo "A driver:<br />";
echo "Name:". $row[ FirstName ] . " " . $row[ LastName ]."<br />";
echo "Latitude:". $row[ CoordLat ]."<br />";
echo "Longitude:". $row[ CoordLong ];
$driverlat = $row[ CoordLat ];
$driverlong = $row[ CoordLong ];
你们根本不需要 lo。
Just do $row = mysql_fetch_array($result); on it s own separate line.
This will display the first row result.
您可在休息时间结束时推出<条码>突破;。 然后只处理第一行。
更好的办法是不使用 lo: 仅指定<代码>$row,并填写。
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