我有一个html输入箱,但只有数字数据。 我如何执行?
I am trying to create a search text-field like on the Apple website. The HTML looks like this: <div class="frm-search"> <div> <input class="btn" type="image" src="http://www....
我有一个html输入箱,但只有数字数据。 我如何执行?
你可以使用超文本5来验证你的输入类型,而不使用 Java本。 然而,这种方法没有得到所有浏览器的支持。
<input type="number" name="quantity" min="1" max="5">
利用以下属性具体限制(如here):
如果所输入的案文有点,你将需要开展一些活动来验证。 见抽样守则
<>JS
function isValidChar(char){
var txt = char;
var found = false;
var validChars = "0123456789"; //List of valid characters
for(j=0;j<txt.length;j++){ //Will look through the value of text
var c = txt.charAt(j);
found = false;
for(x=0;x<validChars.length;x++){
if(c==validChars.charAt(x)){
found=true;
break;
}
}
if(!found){
//If invalid character is found remove it and return the valid character(s).
document.getElementById( txtFld ).value = char.substring(0, char.length -1);
break;
}
}
}
<><><><>>><>>>>><>>>>>>
<input type="text" id="txtFld" onKeyup="isValidChar(this.value);" />
见以下工作文件:jsfiddle。
虽然这部法典是你知道如何使用常规表述或分类的比喻的长点。
选择最低数目和最高比率:
legend {
background-color: #000;
color: #fff;
padding: 3px 6px;
}
.output {
font: 1rem Fira Sans , sans-serif;
}
input,
label {
width: 43%;
}
input {
margin: 1rem 0;
}
label {
display: inline-block;
font-size: .8rem;
}
input:invalid + span:after {
content: ✖ ;
color: #f00;
padding-left: 5px;
}
input:valid + span:after {
content: ✓ ;
color: #26b72b;
padding-left: 5px;
}
<span class="validity"></span>
<input type="number" id="userId" name="userId"
placeholder="Min: 1, max: 10000"
min="1" max="10000" />
<span class="validity"></span>
号码是你想要“123a”返回NAN的功能
par par
<input type="text" id="txtFld" onblur="if(!Number(this.value)){alert( not a number );}" />
引证该法典。 甚至还从事剪辑工作。
<SCRIPT Language ="VBScript">
sub onlyNumber(idBox)
Set objInl = CreateObject("VBScript.RegExp")
objInl.Global = True
objInl.Pattern = "[^0-9-.]"
document.getElementById(idBox).value = objInl.Replace(document.getElementById(idBox).value, "")
set objInl = nothing
end sub
</SCRIPT>
<input type="text" id="txtFld" onKeyup="onlyNumber(this.id);" />
<input name="txtnumbersOnly" type="text" onkeypress="if (event.keyCode < 45 || event.keyCode > 57) event.returnValue = false;">
利用 j印功能作为有效器。 或者你也可以获得 j。
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