Question

试图在有系统安装的含水层机器上写一个简单的文字,以显示使用 whi尾阵列的时间区清单。至今:

tzones=$(timedatectl list-timezones)
arr=( $tzones )
count=0
for i in "${arr[@]}"; do allzones[$count]=$(echo ""$i""); ((count=count+1)); done
for i in "${allzones[@]}"; do echo $i; done #So I know I have a list of items in quotes at this point
whiptail --title "Time zone" --menu "Select time zone" 25 78 16 "${allzones[@]}"

Bash keeps spitting out a help menu for whiptail. I ve only just started messing with whiptail and I ve been at this script a while so not sure what I m missing.

Answer 1

你们似乎希望使用连续编号作为标签。您可在各时区清单中使用<代码>cat -n,以便按一定数目预先排列。由于时区没有空间,因此没有必要使用阵列或进一步照顾间隔。

list=$(timedatectl list-timezones | cat -n)
whiptail --title "Time zone" --menu "Select time zone" 25 78 16 $list

The menu will look something like this:

─────────┤ Time zone ├────────

Select time zone

    1   Africa/Abidjan
    2   Africa/Accra
    3   Africa/Addis_Ababa
    4   Africa/Algiers
    :   :

Answer 2

The last arguments to the --menu option of whiptail must be a sequence of pairs of tag and item, where the chosen tag is send to stderr. Then the array allzones should look like 0 Africa/Abidjan 1 Africa/Accra ...

Then would you try something like:

#!/bin/bash

tzones=( $(timedatectl list-timezones) )
for (( i = 0; i < ${#tzones[@]}; i++ )); do
    allzones+=("$i" "${tzones[$i]}")
done
whiptail --title "Time zone" --menu "Select time zone" 25 78 16 "${allzones[@]}"

If you want to assign a variable to the chosen tag, modify the last line as:

val=$(whiptail --title "Time zone" --menu "Select time zone" 25 78 16 "${allzones[@]}" 3>&1 1>&2 2>&3)

echo "$val"     # just to test

If you want to suppress the numbers, put --notags option to whiptail command.

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