Question

在一个项目中使用j Query nestedSortable plugin 。当一个清单项目被移动时,我将阵列编成序号,将其保存到我的布局。我担心要从PHP阵列中重新列出超文本。或许是因为时间晚:

我有以下阵列:

Array
(
    [list_4] => root
    [list_3] => 4
    [list_1303966373] => 3
    [list_1] => 1303966373
    [list_5] => 1
    [list_2] => 1
    [list_6] => root
)

它应当提出这样的清单。

<ol>
<li id= list_4 >value 4
  <ol>
    <li id= list_3 >value 3
      <ol>
        <li id= list_1303966373 >value 1303966373
          <ol>
            <li id= list_1 >value 1
              <ol>
                <li id= list_5 >value 5</li>
                <li id= list_2 >value 2</li>
              </ol>
            </li>
          </ol>
        </li>
      </ol>
    </li>
  </ol>
</li>
<li id= list_6 >value 6</li>          
</ol>

(如果价值不变,它们只是为了显示。)

超文本清单可能具有任何深度。

我的大脑已经死亡,我无法工作。没有人提出建议? 我恳请你为友爱而 co。另外,还有一座城堡。

感谢:

Answer 1

这里有:

<?php
  $tree = array(
    "list_4" => "root",
    "list_3" => "list_4",
    "list_1303966373" => "list_3",
    "list_1" => "list_1303966373",
    "list_5" => "list_1",
    "list_2" => "list_1",
    "list_6" => "root",
 );
 function getChildrenLists($tree){
    $tree2 = array();
    foreach($tree as $child => $parent){
       if(!array_key_exists($parent, $tree2)) $tree2[$parent] = array();
       $tree2[$parent][] = $child;
    }
    return $tree2;
 }

 function renderTree($tree2, $parent = "root"){
    if($parent != "root") echo "<li id= $parent > value $parent
";
    $children = $tree2[$parent];
    if(count($children) > 0){ //If node has children
       echo "<ol>
";
       foreach($children as $child)
          renderTree($tree2, $child);
       echo "</ol>
";
    }
    if($parent != "root") echo "</li>
";
 }
 $tree2 = getChildrenLists($tree); 
 renderTree($tree2);

?>

我想我的 co! Hehe。希望会有所助益。

友情链接