Question

我把这种方法称作我的控制员:

delete_heard_timeline_event(current_user.id, @showable_video.user.id, @showable_video.video.id)

我的榜样是:

  def delete_heard_timeline_event(actor_id, subject_id, secondary_subject_id)
      TimelineEvent.find_by_actor_id_and_subject_id_and_secondary_subject_id_and_event_type(actor_id, subject_id, secondary_subject_id,  heard_event ).destroy
  end

为什么铁路告诉我,这种方法没有界定?

Answer 1

如果您将这一方法界定为<代码>instance。请将此称为:

a = YourModelName.new
a.delete_heard_timeline_event(your_parameters)

and if this methods is class method so call:

YourModelName.delete_heard_timeline_event(your_parameters)

Answer 2

我已经看到答案,但回答你的问题:

if this NoMethodError pops out because of this line:

find_by_actor_id_and_subject_id_and_secondary_subject_id_and_event_type

I think Rails can handle max 3 conditions and you have 4 there.

而由于你处于铁路3号,你可以这样做:

class TimelineEvent
  def self.delete_heard_event(actor_id, subject_id, sec_id)
    self.scoped.where(:actor_id => actor_id,
     :subject_id => subject_id,
     :secondary_subject_id => sec_id,
     :event_type =>  heard_event ).first.try(:destroy)
  end
end

最终的工业方法试图在其参数中发射一种方法,但仅限于非本国物体,因此,你可以安全地将其称作错误参数。

然后是:

TimelineEvent.delete_heard_event(current_user.id, @showable_video.user.id, @showable_video.video.id)

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