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一起编译几个文件?
原标题:Compile several files together?

我有

  • Data.cpp
  • Data.h
  • User.cpp
  • User.h
  • main.cpp

Main.cpp需要data.cpp和user.cpp。如何链接或编译它们?它们都在同一个目录中?(请更具体一点,比如先编译哪个文件。)

我的系统是:Mac OS X,g++编译器在终端。

最佳回答

最简单的方法:

g++ Data.cpp User.cpp main.cpp

更高级的方法:使用makefile

问题回答

试试这个:

g++ main.cpp Data.cpp User.cpp -o myexecutable

所有源文件都是单独编译的,因此顺序并不重要。编译完成后,g++也会进行链接。

Compile each one seperately to object files. Then link the object files to an application.

我猜你说错话了:

Main.cpp是否不需要user.cpp:他只需要定义在user.cpp中实现的类型。这就是为什么您只需要在Main.cpp中包含user.h

通常,每个.cpp文件都会变成自己的翻译单元,并提供不同的object文件。然后,当链接过程发生时,将组装这些文件。

基本上,步骤是:

  1. For every source file (.cpp), you generate an object file (compilation).
  2. You assemble these object files into the resulting binary (linking).

通常,人们使用Makefile或更好的工具:SConstruct来自动化这些步骤。

SConstruct很好,因为它还在编译前解析源文件并构建依赖树,以确保一切顺利。

最快的方法是

g++ main.cpp Data.cpp User.cpp -o program_name




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