我有
- Data.cpp
- Data.h
- User.cpp
- User.h
- main.cpp
Main.cpp需要data.cpp和user.cpp。如何链接或编译它们?它们都在同一个目录中?(请更具体一点,比如先编译哪个文件。)
我的系统是:Mac OS X,g++编译器在终端。
我有
Main.cpp需要data.cpp和user.cpp。如何链接或编译它们?它们都在同一个目录中?(请更具体一点,比如先编译哪个文件。)
我的系统是:Mac OS X,g++编译器在终端。
最简单的方法:
g++ Data.cpp User.cpp main.cpp
更高级的方法:使用makefile
试试这个:
g++ main.cpp Data.cpp User.cpp -o myexecutable
所有源文件都是单独编译的,因此顺序并不重要。编译完成后,g++也会进行链接。
Compile each one seperately to object files. Then link the object files to an application.
我猜你说错话了:
Main.cpp
是否不需要user.cpp
:他只需要定义在user.cpp中实现的类型。这就是为什么您只需要在
Main.cpp中包含
user.h
。
通常,每个.cpp
文件都会变成自己的翻译单元,并提供不同的object文件。然后,当链接过程发生时,将组装这些文件。
基本上,步骤是:
.cpp
), you generate an object file (compilation).通常,人们使用Makefile
或更好的工具:SConstruct
来自动化这些步骤。
SConstruct
很好,因为它还在编译前解析源文件并构建依赖树,以确保一切顺利。
最快的方法是
g++ main.cpp Data.cpp User.cpp -o program_name
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