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SQL-返回所有行,但非唯一行合并为一行(执行算术运算)?
原标题:SQL - return all rows, however non-unique rows are merged into one (arithmetic performed)?
  • 时间:2011-05-25 17:37:50
  •  标签:
  • sql

我有一个表,其中列B、C和D可以被视为标识符,列E-I是值。根据标识符,将存在一些非唯一的行,即B、C和D的值与其他行的值匹配(可能不止一行匹配)。

我想要一个返回所有行的查询,除了那些非唯一的行。在这些情况下,我希望只返回一行,并对其值求和,只有一个例外,即列E。这应该是相对于列F的加权平均值,即对于每个匹配行,返回的值应该是E*F/F的和

例如

E, F  
7, 1  
9, 4  
E = (7*1 + 9*4)/(1+4) = 8.6

我可以使用什么查询来返回所需的结果集?

非常感谢所有的帮助!

最佳回答

我认为应该这样做:

select B, C, D, sum(E*F) / sum(F), sum(F), sum(G), sum(H), sum(I)
from MyTable
group by B, C, D
问题回答
SELECT B, C, D,
       SUM(E * F) / SUM(F) AS E_WEIGHTED,
       SUM(F) AS F_SUM,
       SUM(G) AS G_SUM,
       SUM(H) AS H_SUM,
       SUM(I) AS I_SUM
  FROM TableX
GROUP BY B, C, D

通常,GROUP BY子句将合并共享重复值的行(在GROUP BY子句中命名的列)。

SELECT B,C,D,SUM(E*F)/SUM(F), SUM(F), SUM(G), SUM(H), SUM(I)
FROM my_table
GROUP BY B,C,D;




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