我很难从哪里入手。我从外部网站获取信息，并将一些内容放在我的页面上。我想我需要做两件事。1.一个谷歌搜索，在给定我当前对象的名称的情况下，获取顶部搜索的url。2.一种检查结果来源并输出具有特定类的标签的信息的方法。
为了更好地解释这一点，我将创建一个假设情况：假设我有一个列出床垫并给出评论的网站。说我想添加其他网站的评论，在这个网站上有一个像3.5/5的标签。然后我想显示这篇评论以及到外部页面的链接。有没有一种方法可以像“site:http://mattressreviewsite/@matress.name”，提取顶部url，然后在源代码中搜索字符串“class=rating”，并在我的视图中显示它？
感谢您的帮助或指导。我使用的是Rails3。
为此，您需要一个HTTP客户端（httparty，net/HTTP默认值），并进行一些解析以获得所需的结果。
去研究谷歌的url模式（据我记忆，它是google.com？q=search_string），并使用http客户端进行请求（get/post）。分析结果（也有许多HTML解析器宝石可用），以获得您所需要的内容以及任何后续的HTTP请求。别忘了谷歌的“我很幸运”功能，它只返回一个结果。
祝你一切顺利！
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