Question

我自己教授了正文,如果有人知道对这一岩石、纸张、雕刻游戏采取更有效的做法,那是荒谬的。

cout << "Pick 1, 2, or 3 for Rock, Paper, or Scissors
> ";

// ...

int match = guess - botGuess;

switch (match) {

case 0:
    cout << tie;
    break;
case -1:
case 2:
    cout << lose;
    break;
case -2:
case 1:
    cout << win;
}

我将游戏的9个可能安排简化为这5个不同案例,但我要知道,是否能够更快地玩.。

Answer 1

对于这种小问题,我使用的是看管表,而不是逻辑表。缩略语

#include <iostream>
#include <array>

constexpr std::array<const char*,3> names = {"Rock","Paper","Scissors"};
constexpr std::array<const char*,3> outcomes = {"Draw","win","Lose"}; 
constexpr std::array<std::array<int,3>,3> results = {{{0,2,1},{1,0,2},{2,1,0}}};

int main() {
    for ( int j=0; j<3; ++j ) {
        for ( int k=0; k<3; ++k ) {
            int result = results[j][k];
            std::cout << names[j] << " x " << names[k] << ": " << outcomes[result] << std::endl;
        }
    }
}

印刷

Rock x Rock: Draw
Rock x Paper: Lose
Rock x Scissors: win
Paper x Rock: win
Paper x Paper: Draw
Paper x Scissors: Lose
Scissors x Rock: Lose
Scissors x Paper: win
Scissors x Scissors: Draw

Godbolt: https://godbolt.org/z/Gxa5vKsGv

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