在终端中运行此命令后,我收到一条Segfault错误消息输出:
bash-3.2$ a.out < testfiles/inputs/tst1.txt 2> err.txt
[2]+ Done gedit err.txt
Segmentation fault
a.out只是在运行一个排序算法。
现在我的问题是如何将Seg错误消息重定向到err.txt文件中。
使用2>;或者其他变体似乎不起作用。
提前谢谢。
在终端中运行此命令后,我收到一条Segfault错误消息输出:
bash-3.2$ a.out < testfiles/inputs/tst1.txt 2> err.txt
[2]+ Done gedit err.txt
Segmentation fault
a.out只是在运行一个排序算法。
现在我的问题是如何将Seg错误消息重定向到err.txt文件中。
使用2>;或者其他变体似乎不起作用。
提前谢谢。
使用重定向,你不能。它不是你程序的输出,而是运行你程序的程序的输出。无论如何,重定向它通常是个坏主意。
这样可以:
$ { ./a.out; } 2> err.txt
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