通常,当你创建<代码>Dictionary<Tkey, TValue>时,你必须首先去,通过在字典上添加字句。
我有<代码>Dictionary<string, mycontainer>,其中
mydictionnary [“SomeName”].Add(myobject);
,未明文要求每当字典上存在一个有上述名称的集装箱时,就建造我的集装箱。
我想知道,这是否是一个好的想法,或者我是否应当明确制造新的我的物体?
通常,当你创建<代码>Dictionary<Tkey, TValue>时,你必须首先去,通过在字典上添加字句。
我有<代码>Dictionary<string, mycontainer>,其中
mydictionnary [“SomeName”].Add(myobject);
,未明文要求每当字典上存在一个有上述名称的集装箱时,就建造我的集装箱。
我想知道,这是否是一个好的想法,或者我是否应当明确制造新的我的物体?
您应使自己的班子达到<代码>。 Dictionary<TKey, List<TItem>>。
索引员希望:
public List<TItem> this[TKey key] {
get {
List<TItem> retVal;
if (!dict.TryGetValue(key, out retVal))
dict.Add(key, (retVal = new List<TItem>(itemComparer)));
return retVal;
}
}
Might as well do myCustomClass.Add ( key, subkey, Value );
so that the Code can be accessible and intellisense will Guide it s use.
我要谈的是明确的法典,即索引员的间接超负荷实际上不是一个共同的情况,在几个月里,其他人将读一下你的法典,这很可能是 b的。
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