One of the many possible solution

Question

绕过 j/j

/*jshint strict: true */
var myModule = (function() {
    "use strict";

    var privVar = true,
        pubVar = false;

    function privFn() {
        return this.test; // -> Strict violation.
    }

    function pubFn() {
        this.test =  public ; // -> Strict violation.
        privFn.call(this); // -> Strict violation.
    }

    return {
        pubVar: pubVar,
        pubFn: pubFn
    };

}());

myModule.pubFn();

我的理解是,在一项职能声明中使用<代码>即<>>ts造成这种情况,但我阅读了一些Crockford撰写的论文,他说,这种违反行为的目的是防止全球变化的污染,但此处唯一的全球变量是明确定义“的Im。其他一切都属于直接职能范围,我应当能够使用<条码>,即<条码>,以提及该模块。

我如何能够采纳这种模式的想法?

<>Update: 如果我使用职能表述而不是声明,这似乎是工作,

var pubFn = function () { ...

I m not a fan of this format though, prefer to have the function name and named params closer and the declaration looks/feels cleaner. I honestly don t see why this is throwing the violation - there s no reason for it in this pattern.

Answer 1

JSHint有option , 称validthis:

[...] suppresses warnings about possible strict violations when the code is running in strict mode and you use this in a non-constructor function [...], when you are positive that your use of this is valid in strict mode.

Use it in the function that JSHint is complaining about, which in your case, would look like this:

function privFn() {
    /*jshint validthis: true */
    return this.test; // -> No Strict violation!
}

function pubFn() {
    /*jshint validthis: true */
    this.test =  public ; // -> No Strict violation!
    privFn.call(this); // -> No Strict violation!
}

似乎很难具体指出,在适用的每一职能中,如果你把选择放在你的模块功能上,你可能会躲避genuine严格的模式违反。

Answer 2

这里的真正问题是,如果你在module context(从window,如果不是严格的话。如果《欧洲常规武装力量条约》要求,这项职能将失败。

这是因为,从欧洲常规武装力量内部要求,这些职能没有 Owner(目标),而所交接的模块目标是职能的所有者,只要这些职能来自欧洲常规武装力量外部,例如this === 缩略语 http://un.org/Depts/DGACM/index_spanish.htm
严格的模式和JSLint/JSLint都试图帮助你,你绝不应忽视这些错误/警告,而是说明他们为什么要警告你。
如果你100%确信<代码>privFn,pubFn,等在任何产生警告的职能中,不会被称作任何地点,而是放在你的模块之外。或者,《欧洲常规武装力量条约》中的一项评论将防止联合企业对模块内的任何功能产生这一错误。

One of the many possible solution

储存<代码>this(例如 Self)的范围,以明确提及该模块。这将表明并确保你的意图。

/*jshint strict: true */ var myModule = (function() { "use strict"; var privVar = true, pubVar = false, self = this; function privFn() { return self.test; } function pubFn() { self.test = public ; //privFn.call(this); // Will have no effect, as `privFn` does not reference `this` privFn(); } return { pubVar: pubVar, pubFn: pubFn }; }()); myModule.pubFn();

Answer 3

Unfortunately, this is the intended error for this setup since jslint/jshint don t know the function declared in global context is to be later used as an object method.

One of the many possible solution

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