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循环体内重复随机编号
原标题:repeated random numbers in a loop [duplicate]
  • 时间:2011-06-14 14:09:40
  •  标签:
  • c++
This question already has answers here:
Closed 12 years ago.

Possible Duplicate:
Repeated random number in a loop

感谢此前的评论意见,我更新了该守则。

首先,主要职能是:

int main ()
{
//DefineRelationstozero (); //All predecessors are set to -1
srand((unsigned)time(0));
.......
......
......
for (int k=0;k<iterationnumber;k++)
{
.....
RandomKey ();//i call randomkey for every iteration
}...

void RandomKey ()
{


        for (int k=0;k<ActivityNumber;k++)
         {

        Act_num[k].Priority=(rand()%10000)*0.0001;//random number

         }


        for (int i=0;i<ActivityNumber;i++)
           arr[i]=Act_num[i].Priority;               

....

循环:对于每一代人来说,错误数字完全相同。

问题回答

maybe Act_num[k]。 优先事项尚未确定。 请:

(rand()%10000)*0.0001

it gives you number from <0, 0.999>. So, if Act_num[k].Priority is integer then you get floor from this random number. So it s 0 for all time





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