我试图学会如何利用C++改变记忆地点,在用地雷Sweeper做饭时,我注意到,当钟点的记忆价值为1101,1004800时,这时20秒钟。 1101529088位数为21秒。 请允许我向我解释一下,这些10位数之间的长数转换为10基数?
他们正在使用浮体代表时间。 这里有一项方案,将你的 in化物转换成浮动:
#include <stdio.h>
int main() {
int n = 1101004800;
int n2 = 1101529088;
printf("%f
", *((float*)&n));
printf("%f
", *((float*)&n2));
return 0;
}
产出:
20.000000
21.000000
1101004800 decimal is 0x41A00000 hex, which is the IEEE-754 representation of 20.0. 1101529088 decimal is 0x41A80000 hex, which is the IEEE-754 representation of 21.0.
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