我想用两套物体,特别是具有x和y价值的点类型,以便我能够计算各点的点数,以及各点中存在的数值。 x和 y的最高价值为[1,000,1000],因此,为每个可能点制定独特的散列代码非常容易。
For the actual binning process, can this be done using a Dictionary. Does the GetHashCode get used for this when I add/lookup a Point to the dictionary?
是否有更好的办法去做。
是的,除非你通过习俗审查,在你建立<条码> 字典/条码>时提供海面编码和检查平等,否则将使用Equals 您类型的方法。
为了提供您的习俗洗,机制,你只能凌驾于<条码>之上。 GetHashCode和 Equals 。
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