Question

here is the problem for example

in = "a    b
ab  c
dd";
out = "a b
b c
dd"
Here is my C code

while(c=getchar()!=EOF){
  if(c==   ){
      while( (c1=getchar()) ==    ); // ignore all other contiguous blank
      putchar(c); // output one blank
      putchar(c1);  // output the next non-blank character             
  }
  else putchar(c);
}

Can I have an implementation with shrinked size?

Answer 1

假设你只删除<条码>:

int c;
char space_found = 0;

while ( ( c = getchar() ) != EOF) {
   if ( (!space_found) || (c !=    ) ) { // if the previous is not a space, or this is not a space
       putchar(c);
   }
   space_found = (c ==    ); // (un)set the flag
}

你们可以改变这一结构,以检查任何具有简单宏观特征的白色空间:

#define is_white_space(X) ( ( (X) ==     ) || ( (X) ==  	  ) || ( (X) ==  
  ) )

替换<代码>c =。

Answer 2

如果你不考虑对“字数”规模的人为限制,那么缩短字眼非常容易:

// pick your limit here:
char word[256];

// and be sure the length here matches:
while (scanf("%255s", buffer))
    printf(" %s", buffer);

Answer 3

Attempt to read a character.
If the input buffer is not empty, output the character previously read. Otherwise skip to step 6.
If the character previously read is a space, keep getting characters until you receive a non-space character.
If the input buffer is not empty, output the recently read character.
Go to step 1.
End Implementation

Sample implementation:

while ((c = getchar ()) != EOF)
  {
    putchar (c);
    if (c ==    )
      {
        while ((c = getchar ()) ==    )
          {}
        if (c != EOF)
          {
            putchar (c);
          }
      }
  }

友情链接