Question

我正在讨论一个<代码>。 UncaultyntaxError: Unexpected end of content at the following Code.

var dataURL = "LineChartController?tp=" + tpAtt + "&dept=" + dept + "&date=" + dateMY;
               alert(dataURL);
               var JSONdata = jQuery.ajax({
                              type: "GET",
                              url: dataURL,
                              async: false
                              }).responseText;

var psSeriesData2 = JSON.parse(JSONdata);

我正在尝试寻找解决办法。这是我采取的步骤。

Ensuring the JSONdata is correct - checked via http://www.jsonlint.com/ and Ensuring that I have closed all brackets

JSON数据格式如下:

[{"Dates":["1-10","2-10","3-10","4-10","5-10","6-10","7-10","8-10"],"psScores":[78.78787878787878,79.7979797979798,78.78787878787878,78.78787878787878,78.78787878787878,79.7979797979798,79.7979797979798,76.92307692307693]}]

我这样做的另一点是,我正在使用造成错误的原型js和其他javascript图书馆。

Uncaught TypeError: Object function $(element) {
   if (arguments.length > 1) {
      for (var i = 0, elements = [], length = arguments.length; i < length; i++)
      elements.push($(arguments[i]));
      return elements;
   }
   if (Object.isString(element))
      element = document.getElementById(element);
      return Element.extend(element);
   } has no method  ajax

我通过论坛进行搜索,发现解决办法是将Jajax美元改为“Query.ajax”,然而,此后,“代码” UncaultyntaxError: Unexpected end of content差错。

在这个问题上给予任何帮助。问题是什么想法?

Answer 1

您的服务器是否具体规定了响应类型/json? 如果是的话, j子会自动放弃结果,甚至收回。顺便说一句,你再次试图 par平已经教过的东西。

Try specifying the dataType in your call, and jQuery will pre-parse the result for you.

You should also try to do it asynchronously if possible.

var dataURL = "LineChartController?tp=" + tpAtt + "&dept=" + dept + "&date=" + dateMY;
var JSONdata = jQuery.ajax({
     type: "GET",
     dataType: "json",
     url: dataURL
}).done(function(jsonData){
     // do something with the data, it should already be parsed
     alert(jsonData.length); // your data sample is an array, see if it gets a length back
}).fail(function(xhr){
     // uh oh, we failed.. you should always handle failures too.
});

Answer 2

I had the same issue, but with a different root cause. in my API controller, I had

public HttpResponseMessage Invite(Invitation invitation)
{
   var response = Request.CreateResponse(HttpStatusCode.OK);
   return response;

The solution to the problem was to add a response message:

 var response = Request.CreateResponse(HttpStatusCode.OK, "invitation sent");

这使我的神学方法提供了它希望得到的预计投入。

Answer 3

如你需要使用JQuery snoConflict(),以便原型能够保留$。

例:

<script type="text/javascript" src="other_lib.js"></script>
<script type="text/javascript" src="jquery.js"></script>
<script type="text/javascript">
  $.noConflict();
  jQuery(document).ready(function($) {
    // Code that uses jQuery s $ can follow here.
  });
  // Code that uses other library s $ can follow here.
</script>

文件:http://api.jquery.com/jQuery.noConflict/"rel=“nofollow”http://api.jquery.com/jQuery.noConflict/

友情链接