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在一个产生zy清单的方法中,如果一不返回,会发生什么情况?
原标题:in a method which produces lazy list, what happens if i return nothing?
  • 时间:2011-08-26 00:00:30
  •  标签:
  • c#

it seems this code is valid. I am wondering what if getTest(1)

    IEnumerable<int> getTest(int n)
    {
        if (n == 0)
            yield return 1;
        else
            ;
    }
最佳回答

它将退回一个空的但非核的<编码>IE numberable<int>。

一旦您标明了一种作为导体的方法(使用yield,在方法的任何地点,可以执行zero或。 <代码>收益/代码>,以便按顺序回归数据。

In fact, the simplest way to get an empty IEnumberable is IEnumerable<T> Empty() { yield break; }.
Or just call Enumerable.Empty<T>().

问题回答

It just returns an empty, although fully "valid", enumerable. Everything went exactly as expected.





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