Question

What is the most idiomatic way with NUnit 2.6 to check equality of a property of an exception?

守则一

Assert.That(() => someObject.MethodThrows(),
  Throws.TypeOf<SomeException>().With.Property("Data").Count.EqualTo(3), /* Data is a collection */
  "Exception expected");

我可以使用<代码>Assert表示,但这似乎过于复杂和不必要的:

  Assert.AreEqual(3,
    Assert.Throws<SomeException>(
      () => someObject.MethodThrows(),
      "Exception expected").Data.Count);

<><>>> 事实上,第一部法典就是行之有效的。我不知道为什么在提出这一问题之前没有几次工作。

Answer 1

我可以谈一下六大特,但就五大特而言,我可以谈一下:

Public Class MyException
    Inherits Exception
    Public Property SomeList As New List(Of String) From {"hello", "world"}
End Class

<TestFixture()>
Public Class TestClass1
    Public Shared Sub DoSomething()
        Throw New MyException()
    End Sub

    <Test()>
    Public Sub TestExample()
        Assert.That(Sub() DoSomething(), Throws.TypeOf(Of MyException)().With.Property("SomeList").Count.EqualTo(3))
    End Sub
End Class

produces this following error message:

Expected: <ClassLibrary1.MyException> and property SomeList property Count equal to 3
But was:  < "hello", "world" >

难道这只是六国联会的倒退吗?

Answer 2

我将这样做:

var exception = Assert.Throws<SomeException>(() => someObject.MethodThrows(),
                                             "Exception expected")
Assert.AreEqual(3, exception.Data.Count);

这是你最清楚的:

Unlike your first example, this is refactoring safe
It asserts one thing at a time, not multiple like both of your examples.

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