Question

这可能像一个sil然的问题,但我试图找到一个没有多大成功的解决办法。我收到一份名单:

for v in sorted(list):
    print v


[885.1, 12824]
[885.1, 19843]
[885.11, 1319]
[885.12, 1155]
[885.13, 12844]
[885.14, 33602]
[885.15, 11324]
[885.16, 44040]
[885.2, 119283]
[885.3, 8424]

我通过我的清单,利用分类的功能——然而,如上所述,将ASCII中的项目归类为人类可读顺序的浮动? 即:

[885.1, 19843]
[885.2, 119283]
[885.3, 8424]
[885.11, 1319]
[885.12, 1155]
[885.13, 12844]
[885.14, 33602]
[885.15, 11324]
[885.16, 44040]

Do I need to create an index of somekind? Convert my floats to ints? Any help much appreciated.

David。

Answer 1

将浮标改为先铺,然后按“:

sorted(a, key=lambda x:map(int, str(float(x[0])).split(".")))

Answer 2

这称为“猎物”(自然)。 http://www.skynet.ie/~caolan/Packages/python-natsort.html”rel=“nofollow” http://www.skynet.ie/~caolan/Packages/python-natsort.html。 (后经审判)。或许可以帮助你。

^{Oh and that s not necessarily ASCII sort, it s just the number order, you know, like the real axis}

Answer 3

你们需要发挥比较功能。类似于:

sorted(list, cmp=lambda x, y: cmp(x[0], y[0]))

Just write the function you need for what you want and plug it in.

You ll probably want something like a reverse radix sort.

Answer 4

This is kind of a hack, but:

a = [
    [885.1, 19843],
    [885.1, 12824],
    [885.11, 1319],
    [885.12, 1155],
    [885.13, 12844],
    [885.14, 33602],
    [885.15, 11324],
    [885.16, 44040],
    [885.2, 119283],
    [882.8, 8424],
    [882.75, 8424],
    [885.3, 8424]
]

for v in sorted(a, key=lambda t: str(t[0]).split(".")[0] + ("%05d" % int(str(t[0]).split(".")[1])) + "," + str(t[1])):
    print v

Result is

[882.8, 8424]
[882.75, 8424]
[885.1, 12824]
[885.1, 19843]
[885.2, 119283]
[885.3, 8424]
[885.11, 1319]
[885.12, 1155]
[885.13, 12844]
[885.14, 33602]
[885.15, 11324]
[885.16, 44040]

免责:这假定在ci点之后的5个地方。相应调整。

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