I m 试图作出这一改变
(To_days( now( )) - TO_DAYS( o.date_payed)) days1,
(To_days( now( )) - TO_DAYS( o.date_purchased)) days2,
这项工程罚款,但Im试图作两个改动,第一个变化是,我只想到days1,如果是To_days(现在(......))”的结果的话。 - 排在上的空投是第二种。
第二项修改是,不要使用<代码>To_days,而是采用某种方式只使用一周日,欢迎任何想法。
关于第一个问题,可使用, ie
SELECT IF((o.date_payed IS NOT NULL)&&(To_days(now()) != TO_DAYS(o.date_payed))
,To_days(now()) - TO_DAYS(o.date_payed)
,To_days(now()) - TO_DAYS(o.date_purchased)
) AS days1 ...
http://dev.mysql.com/doc/refman/5.5/en/date-and-time-Functions.html#Function_date-format”rel=“nofollow”>date_format function,iecode>DATE_FORMAT(o.date_ Paied, %w )。
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