I have MMDDYY dates, i.e. today is 111609
How do I convert this to 11/16/2009, in Python?
I suggest the following:
import datetime
date = datetime.datetime.strptime("111609", "%m%d%y")
print date.strftime("%m/%d/%Y")
This will convert 010199 to 01/01/1999 and 010109 to 01/01/2009.
date = 111609
new_date = date[0:2] + / + date[2:4] + / + date[4:6]
>>> s = 111609
>>> d = datetime.date(int( 20 + s[4:6]), int(s[0:2]), int(s[2:4]))
>>> # or, alternatively (and better!), as initially shown here, by Tim
>>> # d = datetime.datetime.strptime(s, "%m%d%y")
>>> d.strftime( %m/%d/%Y )
11/16/2009
one of the reasons why the strptime() approach is better is that it deals with dates close to contemporary times, with a window, i.e. properly handling dates in the latter part of the 20th century and dates in the early part of the 21st century properly.
Incomplete but here s an idea
11/16/2009
date_var = ("11/16/2009")
datetime.date.replace(year=2009, month=11, day=16)
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I have MMDDYY dates, i.e. today is 111609 How do I convert this to 11/16/2009, in Python?
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