Question

I am having a problem scanning chars into an array. Every time I do it will skip the next scan and go to the next. I know what is happening because the input also adds to the input but I do not know how to remedy the cause of it. Here is some sample code:

char charray [MAX], ffs;
int inarray [MAX], i;


for (i = 0; i < MAX; i++)
{
    charray[i] = getchar();
    printf ("%c
",charray[i]);
    scanf ("%d", &inarray[i]);
    printf ("%d
",inarray[i]);
}

Answer 1

您实际上应当直接扫描阵列,而不是使用<条形码>扫描(>%s”)和黄色;。

However your code will work if you add a while(getchar() != ); statement. This will get all characters till the .

charray[i] = getchar();
do{
    c = getchar();
}while(c !=  
  && c!= EOF);
printf ("%c
",charray[i]);
scanf ("%d", &inarray[i]);
do{
    c = getchar();
}while(c !=  
  && c!= EOF);    
printf ("%d
",inarray[i]);

Answer 2

你可以这样做。

while((c = getchar()) !=  
 )
{
    putchar(c);
}

这可以解决你的问题。或者你也可以去学习平等论坛。

Answer 3

您可从标准投入中读到,有2项功能:getchar()和scanf(。你们需要了解他们的工作方式。

getchar() is easy: it returns the next available character in the input stream (or waits for one or returns EOF)

scanf("%d", ...) is more complex: first, it optionally discards whitespace (spaces, enters, tabs, ...), then it reads as many characters as possible to represent an integer, and stops at the first character that can t be used for integers, like a .

由于你在座右翼上座,您的<代码>getchar(>)的电话将具有阻止scanf(>的特性,下个scanf(<>>将从该密码上传。

如果您的投入如<代码>q1w22e333r44>(>/code = 4),则您的方案将发挥作用。

如果你们的意见是这样的话

after the first time through the loop (where charray[0] gets q and inarray[0] gets 1), the getchar() will get leaving the w "ready" for scanf, which of course fails ... and is then "caught" by the next getchar(); and the "22" gets assigned in the 3rd time through the loop (to inarray[2]).

因此,你需要审查你的法典。

另外,<代码>scanf() 回归数值。 <>可见>

if (scanf("%d", &inarray[i]) != 1) /* error */;

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