<><>Input
[[0 0 0 0 0]
[0 4 0 0 0]
[0 1 0 0 0]
[0 1 2 0 0]
[0 1 2 3 0]]
www.un.org/Depts/DGACM/index_spanish.htm 预期产出
[[(0, day00) (0, day01) (0, day02) (0, day03) (0, day04)]
[(0, day10) (4, day11) (0, day12) (0, day13) (0, day14)]
[(0, day20) (1, day21) (0, day22) (0, day23) (0, day24)]
[(0, day30) (1, day31) (2, day32) (0, day33) (0, day34)]
[(0, day40) (1, day41) (2, day42) (3, day43) (0, day44)]]
<><>相关>
a. 对源矩阵进行扫描,并生成一个结果矩阵:
random_matrix = generate_random_matrix(...) # the way you want
result = []
for row in random_matrix:
result_row = []
for value in row:
result_row.append((value, randomDate(...)))
result.append(result_row)
print result # or whatever
采用更短但更细致的加密方法:
result = [
[(value, randomDate(...)) for value in row]
for row in genenerate_random_matrix(...)
]
def o(inputt):
output = []
for i, arr in enumerate(inputt):
n = []
for j, x in enumerate(arr):
n.append((x, "day" + str(i) + str(j)))
output.append(n)
return output
print o([[0, 0, 0, 0, 0],
[0, 4, 0, 0, 0],
[0, 1, 0, 0, 0],
[0, 1, 2, 0, 0],
[0, 1, 2, 3, 0]])
x = [[0, 0, 0, 0, 0,],
[0, 4, 0, 0, 0,],
[0, 1, 0, 0, 0,],
[0, 1, 2, 0, 0,],
[0, 1, 2, 3, 0,],]
enum = enumerate
[[(item, day%02d % (i*10+j)) for j, item in enum(row)] for i, row in enum(x)]
专 员
[[(0, day00 ), (0, day01 ), (0, day02 ), (0, day03 ), (0, day04 )],
[(0, day10 ), (4, day11 ), (0, day12 ), (0, day13 ), (0, day14 )],
[(0, day20 ), (1, day21 ), (0, day22 ), (0, day23 ), (0, day24 )],
[(0, day30 ), (1, day31 ), (2, day32 ), (0, day33 ), (0, day34 )],
[(0, day40 ), (1, day41 ), (2, day42 ), (3, day43 ), (0, day44 )]]
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