什么是执行<条码>的简单公式?
For example, divround(3,2)
and divround(5,2)
both evaluate to 2.
我写了嵌入式的代码,因此我不能依靠图书馆。 我希望该守则对阿拉伯投资机制和国际投资争端解决中心具有通用性,因此也没有任何组装。 我试图弄清NumPy(半至晚)的<代码>np.around(a/b)
什么是执行<条码>的简单公式?
For example, divround(3,2)
and divround(5,2)
both evaluate to 2.
我写了嵌入式的代码,因此我不能依靠图书馆。 我希望该守则对阿拉伯投资机制和国际投资争端解决中心具有通用性,因此也没有任何组装。 我试图弄清NumPy(半至晚)的<代码>np.around(a/b)
Assuming a
and b
are nonnegative, and b
is less than INT_MAX / 2
, the following is a simple implementation:
int divround(int a, int b)
{
int q = a / b;
int r = a % b;
if (2*r > b) {
return q + 1;
} else if (2*r < b) {
return q;
} else if (q % 2) {
return q;
} else {
return q + 1;
}
}
解释:
b
round up and if it s less round down.b/2
exactly, then check if the quotient is even, and if so round down otherwise round up.For example, let s say I want to find a particular word or number in a file. The contents are in sorted order (obviously). Since I want to run a binary search on the file, it seems like a real waste ...
最好、最小、最快、开放的来源、C/C++ 3d 提供方(在3ds max模型的支持下),而不是通用公平市价,
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