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简言之:能否要求有关职能的论点都是关键词?
原标题:python: is it possible to require that arguments to the functions are all keyword?

为了避免出现明显的弊端,我想防止使用某些职能的立场论点。 是否有办法实现这一目标?

最佳回答

只有Adhur 3 能够适当做到这一点(而且你使用了Python3 标签,因此可以罚款):

def function(*, x, y, z):
    print(x,y,z)

使用<代码>**kwargs,除非你稍后核对,否则将允许用户输入any 论点。 此外,它将掩盖真实的论据,以逃避猜测。

<代码>**kwargs不是这个问题的答案。

测试方案:

>>> function(1,2,3)
Traceback (most recent call last):
  File "<pyshell#1>", line 1, in <module>
    function(1,2,3)
TypeError: function() takes exactly 0 positional arguments (3 given)
>>> function(x=1, y=2, z=3)
1 2 3
问题回答

您可以界定一个分母,即如果它的职能是用任何立场论点加以纠正,则使用内观来造成错误。 这使你能够阻止具有某些职能的use立场论点,同时允许你按照你的意愿担任这些职务。

例如:

def kwargs_only(f):
    def new_f(**kwargs):
        return f(**kwargs)
    return new_f

使用:

@kwargs_only
def abc(a, b, c): return a + b + c

因此(类型错误):

abc(1,2,3)

因此,你可以使用:

abc(a=1,b=2,c=3)

更强有力的解决办法是使用<代码>decorator模块。

Disapper: 晚夜回答没有保证!

是的,只是使用<代码>**kwargs,而只读到其中的参数。

def my_function(**kwargs):
    for key, value in kwargs.iteritems():
        print ("%s = %s" % (key, value))

my_function(a="test", b="string")




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