Question

我试图解决Zed Shaw s Learnshed 艰难之路的15个额外信贷问题,但我已陷入了一个问题。该法典如下:

from sys import argv

script, filename = argv

txt = open(filename)

print "Here s your file %r:" % filename
print txt.read()
print "I ll also ask you to type it again:"
file_again = raw_input("> ")

txt_again = open(file_again)
print txt_again.read()

print txt_again.read()

I understand all the code that has been used, but extra credit question 7 asks:

开始<代码>python,并迅速使用 open。通知您如何打开档案和操作read?

I ve tried inputting everything I could think of in terminal (on a mac) after first starting up python with the python command, but I can t get the code to run. What should I be doing to get this piece of code to run from the prompt?

Answer 1

Zed don t topr this particular part of code from within-030. 显然,这部法典正在从你用来援引该书的参数中获取filename的价值,如果你刚刚开始着手处理该书,你就使用了任何参数。

如果是,

filename =  myfilename.txt 
txt = open(filename)

然后,它会发挥作用。

Answer 2

我刚刚开始开放(xyz.txt)

当然,如果是,那当然是没有工作,因为你没有可变的<条码>xyz,即使你这样做,它也不会有个属性<条码>txt。既然是档案名称,你就希望有一个string“xyz.txt”,你通过引文创建:xyz.txt。灰尘处理单一和双重报价的通知大体相同;与C++和Java等语言不同,个人特性没有单独的数据类型——它们只是长1秒。

Answer 3

基本上,就如同本记录一样(我增加了援助的可读性中的空白线):

pax:~$ python 
Python 2.7.1+ (r271:86832, Apr 11 2011, 18:05:24) 
[GCC 4.5.2] on linux2
Type "help", "copyright", "credits" or "license" for more information.

>>> xyz = open ("minimal_main.c")

>>> print xyz.read()
int main (void) {
    return 0;
}

>>> xyz.close()

>>> <CTRL-D>

pax:~$ _

所有这一切都表明,你没有打上“need的纸面,以便进行突击检查,指挥线接口可以大体使用。

Answer 4

。

在终点站开车后,我们使用<代码>开放(档案名称:txt )打开文档,并使用t营运人,我们可以直接使用<代码>read(。

Answer 5

在终点站露天之后,

abc = open ("ex15_sample.txt")
print abc.read()

That should do.

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